Division A - Tie Breaker

by **byualum** on Tue Apr 18, 2006 5:41 pm

From the rmlax.com website on deciding a mulit-team tie:

Record vs Common Out-of-Conference opponent. (All teams must have played the same opponent)

If still a tie, then...
Goal differential between the teams that are tied, (No award greater than 8 allowed for routs)

If still a tie, then...
Goal Differential - total league schedule. (No award greater than 8 allowed for routs)

So...if CSU were to beat CU on Saturday and BYU beats Utah, then there's a three-way tie with CSU, CU and BYU all at 2-1.

Looking at the three schedules, I believe UCSB is the only common out-of-conference opponent (not counting Whittier). Does this mean CSU is the #1 seed as they beat UCSB and BYU and CU both lost?

**Sponsor**

by **onpoint** on Sat Apr 22, 2006 11:46 pm

Oops, I knew this was here. So with the common out of conference opponent being UCSB, CSU does get the #1 seed by virtue of their win over the Gauchos and CU and BYU's losses to them.

by **robinetteja** on Mon Apr 24, 2006 10:01 pm

you got it.

by **CATLAX MAN** on Tue Apr 25, 2006 12:54 am

To me it seems really out of place that games against common out-of conference opponents should decide a multi-team tiebreaker. From the list of tiebreakers, it seems more appropriate to me that the other 2 tiebreakers (conference games) ought to come first. Anyone else have any ideas on this?

by **onpoint** on Tue Apr 25, 2006 7:22 am

The RMLC's tiebreaking procedures are drawn verbatim from the Patriot League's in Division I. If it's good enough for them . . . Fortunately for CSU, it worked out in our favor this year. Unfortunately for UCSB, thier seeding in the WCLL did not.

by **wheelz33** on Tue Apr 25, 2006 7:33 am

just out of curiosity, what if there was more then 1 common out of conference opponent? which opponent would be chosen?