Riddle

Non-lacrosse specific topics.

Postby Gregg Pathiakis on Sat Jan 21, 2006 6:36 pm

tamu33 wrote:Matt Holtz got it right... and he explained it the way it was supposed to be done.

(twins) (not twins - all factors of possibilities)
1 x 1 = 1 -- no factors

2 x 2 = 4 -- 4 x 1 -( correct answer )

3 x 3 = 9 -- 9x1 - (over 7, so no good)

4 x 4 = 16 -- 2 x 8; 1 x 16 (all over 7, so no good)

5 x 5 = 25 -- 25 x 1 (over 7, so no good)

6 x 6 = 36 -- 3 x 12, 9 x 4, 36 x 1, 2 x 18 (all over 7, so no good)

See, we can figure it out because the man was torn between twins and not twins. When the extra info came, we found out that they were not twins. So all we have to do is see what set of numbers are under 7 in their product and in their factors and also when they are twins.... We only have one set that follows those rules. and it is 4.... so the aswer is 4 and 1.


Maybe I am just having a brain cramp, but the original story didn't say their product had to be less than 7, right? So why not a 3-year-old and a 4-year-old with 12 birds in the tree.

And this may be nitpicking, but why can't they be the same age? You can have two three-year olds that aren't twins. If my brother was born 9 months before me, we'd both be 26 right now.
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Postby Gregg Pathiakis on Sat Jan 21, 2006 6:41 pm

tamu33 wrote:City of truth seemed to be answered so here is another one... sorry it took so long... on the weekends I am not on here as much.


What row of numbers comes next?

1
11
21
1211
111221
312211
13112221

This is somewhat tough... it took me a few wrong answers before I got it.


Good one. I've had two guesses so far but neither work out.
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Postby tamu33 on Sat Jan 21, 2006 10:59 pm

Maybe I am just having a brain cramp, but the original story didn't say their product had to be less than 7, right? So why not a 3-year-old and a 4-year-old with 12 birds in the tree.

And this may be nitpicking, but why can't they be the same age? You can have two three-year olds that aren't twins. If my brother was born 9 months before me, we'd both be 26 right now.


No it didn't say that the product had to be under 7 but what we did know was that the second friend was torn between a choice.

3 x 4 = 12 -- 12 x 1, 2 x 6 = if there were 12 birds in the tree than there are two options on how old they are (6-2 and 3-4-- both under 7).

So our friend would need more info (because we only got that one is older) to figure which set would be correct.

So we check our answer of 4 birds by looking at which set of factors (non-twins) and (twins - or in your case same age siblings) show up more than once.

The only number that shows up twice is 4. so our possibilities are 2x2 and 4x1 (that is the dilemma) Once we hear that one is older than the other .... we now know that they are not the same age... so 4-1 is the answer.


Believe me I had 4-3 for the longest time too. So I understand your pain.
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Postby Gregg Pathiakis on Sun Jan 22, 2006 12:03 am

tamu33 wrote:No it didn't say that the product had to be under 7 but what we did know was that the second friend was torn between a choice.

3 x 4 = 12 -- 12 x 1, 2 x 6 = if there were 12 birds in the tree than there are two options on how old they are (6-2 and 3-4-- both under 7).

So our friend would need more info (because we only got that one is older) to figure which set would be correct.

So we check our answer of 4 birds by looking at which set of factors (non-twins) and (twins - or in your case same age siblings) show up more than once.

The only number that shows up twice is 4. so our possibilities are 2x2 and 4x1 (that is the dilemma) Once we hear that one is older than the other .... we now know that they are not the same age... so 4-1 is the answer.


Believe me I had 4-3 for the longest time too. So I understand your pain.


OK... I think I get that explanation... if there were 12 birds in the tree, then the fact that one is older wouldn't allow him to figure it out. But can you get around the non-twins that are the same age? :)
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Re: Riddle

Postby shrekjr on Sun Jan 22, 2006 12:15 am

tamu33 wrote:So I was bored today and found a riddle that stumped me for a bit. So I thought I might challenge everyone. And if you solve it put up your own riddle.

Here's a riddle....
Everyone else in District 8 is in referee meetings all day. Tamu33 is online playing games all day. Who didn't go to the referee meetings? :roll:

I know, you said you had some excuse not to go. Yeah, whatever... :P
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Postby tamu33 on Sun Jan 22, 2006 3:48 am

Everyone else in District 8 is in referee meetings all day. Tamu33 is online playing games all day. Who didn't go to the referee meetings?


Well really I am not required to attend said meetings since I will not be COC this year. But I did have an excuse and today I found out two other people who are exempt from the meetings. And this thread was started on friday .... and the meetings were on saturday in another city.

I will give everyone until sunday at noon to figure out the other riddle.
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Postby shrekjr on Sun Jan 22, 2006 10:15 am

Just giving you a hard time. You didn't miss too much.
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Postby tamu33 on Sun Jan 22, 2006 12:27 pm

What row of numbers comes next?

1
11
21
1211
111221
312211
13112221

This is somewhat tough... it took me a few wrong answers before I got it



The next row is
1113213211
Starting with the second line, every line describes the line before it. In writing, it is:
One One
Two Ones
One Two One One
etc.
etc.
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Postby Gregg Pathiakis on Sun Jan 22, 2006 8:10 pm

tamu33 wrote:
What row of numbers comes next?

1
11
21
1211
111221
312211
13112221

This is somewhat tough... it took me a few wrong answers before I got it



The next row is
1113213211
Starting with the second line, every line describes the line before it. In writing, it is:
One One
Two Ones
One Two One One
etc.
etc.


I like that one... good one!
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Postby Gregg Pathiakis on Wed Jan 25, 2006 1:16 pm

Here's a new one...

Which of the following words does not belong in the list, and why?

Reappear
Caucasus
Inefficiencies
Signings
Arraigning
Horseshoer
Intestines
Appeases
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Postby WaterBoy on Wed Jan 25, 2006 1:29 pm

Inefficiencies.

All of the other words have letters in couplets.
i.e.- signings (2s, 2i, 2g, 2n)

and reappear (2r, 2e, 2a, 2p)

Ineffeciencies (4i, 2n, 3e, 2f, 2c, 1s)

the pairings don't add up.
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Postby laxfan25 on Wed Jan 25, 2006 1:48 pm

You could also say Horseshoer, as the only trade in the group, but I like the couplets idea better.
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Postby WaterBoy on Wed Jan 25, 2006 3:38 pm

I'll add my own little ditty to the great jumble of minds.

Here's one for ya'll.

Angry and hungry are two words that end in '-gry'. There are three words in the English language. What is the third word? Everyone knows what it means and everyone uses it every day.

Any takers?
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Postby Gregg Pathiakis on Wed Jan 25, 2006 3:39 pm

WaterBoy wrote:Inefficiencies.

All of the other words have letters in couplets.
i.e.- signings (2s, 2i, 2g, 2n)

and reappear (2r, 2e, 2a, 2p)

Ineffeciencies (4i, 2n, 3e, 2f, 2c, 1s)

the pairings don't add up.


We have a winner!
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Postby YESIAMAGIRL on Wed Jan 25, 2006 7:28 pm

WaterBoy wrote:I'll add my own little ditty to the great jumble of minds.

Here's one for ya'll.

Angry and hungry are two words that end in '-gry'. There are three words in the English language. What is the third word? Everyone knows what it means and everyone uses it every day.

Any takers?


language.

ohhh i'm so smart!!
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